Mathématiques

Question

Urgent svp, (7x-3)(4x-2)+(2x-3)(7x-3) = 0  AIdez Pls :s

1 Réponse

  • bonsoir

    (7x-3)(4x-2)+(2x-3)(7x-3) = 0
    (7x-3)(4x-2 + 2x-3) =0
    (7x-3)(6x -5) = 0
    soit
    7x -3 = 0
    7x = 3 et x = 3/7

    soit 6x -5 = 0
    6x = 5
    x = 5/6


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